(1/3√27-√24+3√2/3)×√18=?根号
问题描述:
(1/3√27-√24+3√2/3)×√18=?根号
答
1/3√27-√24+3√2/3)×√18
=(√3-2√6+√2)×√18
=3√6-12√3+6