(2+1)(2²+1)(2^4+1)(2^8+1)(2^16+1) 结果保留幂形式
问题描述:
(2+1)(2²+1)(2^4+1)(2^8+1)(2^16+1) 结果保留幂形式
答
原式=(2-1)(2+1)(2²+1)(2^4+1)(2^8+1)(2^16+1)
=(2²-1)(2²+1)(2^4+1)(2^8+1)(2^16+1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)
=2^32-1