x(a-x)(a-y)-y(x-a)(y-a)怎么因式分解

问题描述:

x(a-x)(a-y)-y(x-a)(y-a)怎么因式分解

x(a-x)(a-y)-y(x-a)(y-a)
=(x-y)(a-x)(a-y)
因为同时改变式子中的两个数的符号结果还相等,所以(x-a)(y-a)=(a-x)(a-y)

x(a-x)(a-y)-y(x-a)(y-a)
=x(a-x)(a-y)-y[-(a-x)][-(a-y)]
=x(a-x)(a-y)-y(a-x)(a-y)
=(a-x)(a-y)(x-y)

x(a-x)(a-y)-y(x-a)(y-a)
=x(a-x)(a-y)-y(a-x)(a-y)
=(a-x)(a-y)(x-y)