△ ABC的周长为100cm,如图AE/AB=AF/AC=EF/BC=3/5,△ AEF的周长为________
问题描述:
△ ABC的周长为100cm,如图AE/AB=AF/AC=EF/BC=3/5,△ AEF的周长为________
答
△AEF的周长为=AE+AF+EF
=3/5AB+3/5AC+3/5BC
=3/5(AB+AC+BC)
=3/5*100
=60cm