一道初二的数学题(乘法公式单元)x+1/x=4求:(1)x^2+1/x^2(2)(x-1/x)^2
问题描述:
一道初二的数学题(乘法公式单元)
x+1/x=4
求:(1)x^2+1/x^2
(2)(x-1/x)^2
答
x+1/x=4
两边平方
x^2+2*x*1/x+1/x^2=4^2
x^2+2+1/x^2=16
所以x^2+1/x^2=14
(x-1/x)^2
=x^2-2*x*1/x+1/x^2
=x^2-2+1/x^2
=14-2
=12
答
x^2+1/x^2 =(x+1/x)^2 -2*x*1/x=4^2-2=14
(x-1/x)^2=x^2+1/x^2-2*x*1/x=14-2=12