x^2+y^2-4x+6y+13=0,则xy=?
问题描述:
x^2+y^2-4x+6y+13=0,则xy=?
答
x^2+y^2-4x+6y+13=0
x^2-4x+4+y^2+6y+9=0
(x-2)^2+(y+3)^2=0
x=2,y=-3
xy=-6
答
(x-2)^2+(y+3)^2=0
x-2=0且y+3=0
x=2,y=-3
xy=-6
答
x^2+y^2-4x+6y+13=0
x^2-4x+4+y^2+6y+9=0
(x-2)^2+(y+3)^2=0
x=2
y=-3
xy=-6