已知p=a²+3ab+b²,q=a²-3ab+b²,化简:p-[q-2p-(-p+q)]

问题描述:

已知p=a²+3ab+b²,q=a²-3ab+b²,化简:p-[q-2p-(-p+q)]

p-[q-2p-(-p+q)]
=p-q+2p-p+ q
=2p
p=a²+3ab+b²
代入,得
原式=2(a²+3ab+b²)

p-[q-2p-(-p+q)]
=p-[q-2p+p-q]
=p-(-p)
=2p
=2a²+6ab+2b²