lim(n趋于无穷大)((根号下n^4+n+1)-n^2)(3n-4)=?答案是3/2求详解

问题描述:

lim(n趋于无穷大)((根号下n^4+n+1)-n^2)(3n-4)=?答案是3/2求详解

((根号下n^4+n+1)-n^2)(3n-4)=(n+1)(3n-4)/(根号下n^4+n+1)+n^2),然后分子,分母都除以n^2,可以得极限为3、2