(x-6)(x的平方+x+1)-x(2x+1)(3x-1)计算
问题描述:
(x-6)(x的平方+x+1)-x(2x+1)(3x-1)
计算
答
(x-6)(x²+x+1)-x(2x+1)(3x-1)
=(x³+x²+x-6x²-6x-6)-x(6x²-2x+3x-1)
=(x³-5x²-5x-6)-x(6x²+x-1)
=x³-5x²-5x-6-6x³-x²+x
=-5x³-6x²-4x-6
答
(x-6)(x²+x+1)-x(2x+1)(3x-1)
=(x³+x²+x-6x²-6x-6)-x(6x²-2x+3x-1)
=(x³-5x²-5x-6)-x(6x²+x-1)
=x³-5x²-5x-6-6x³-x²+x
=-5x³-6x²-4x-6
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