因式分解:x(x+1)(x+2)(x+3)-24
问题描述:
因式分解:x(x+1)(x+2)(x+3)-24
答
原式=(x²+3x)(x²+3x+2)-24 设x²+3x+1=a 原式=(a-1)(a+1)-24 =a²-1-24 =a²-25 =(a-5)(a+5) ...
因式分解:x(x+1)(x+2)(x+3)-24
原式=(x²+3x)(x²+3x+2)-24 设x²+3x+1=a 原式=(a-1)(a+1)-24 =a²-1-24 =a²-25 =(a-5)(a+5) ...