-2a^2(2/1ab+b^2)+5a(a^2b-ab^2)
问题描述:
-2a^2(2/1ab+b^2)+5a(a^2b-ab^2)
答
-2a²(ab/2+b²)+5a(a²b-ab²)=a²b[-2(a/2+b)+(5a-5b)]=a²b(-a+2b+5a-5b)=a²b(4a-3b)
-2a^2(2/1ab+b^2)+5a(a^2b-ab^2)
-2a²(ab/2+b²)+5a(a²b-ab²)=a²b[-2(a/2+b)+(5a-5b)]=a²b(-a+2b+5a-5b)=a²b(4a-3b)