2a2+b2+2a+2ab+1=0求a,b的值
问题描述:
2a2+b2+2a+2ab+1=0求a,b的值
答
2a^2+b^2+2a+2ab+1=0
a^2+2ab+b^2+a^2+2a+1=0
(a+b)^2+(a+1)^2=0
a+b=0,a+1=0
a=-1,b=1