f'(x)=g(x),则df(sin^2x)/dx=
问题描述:
f'(x)=g(x),则df(sin^2x)/dx=
答
df(sin^2x)/dx=g(sin^2x)(sin^2x)'=g(sin^2x)2sinxcosx=g(sin^2x)sin2x
f'(x)=g(x),则df(sin^2x)/dx=
df(sin^2x)/dx=g(sin^2x)(sin^2x)'=g(sin^2x)2sinxcosx=g(sin^2x)sin2x