如图,已知∠A=∠B,AA1,PP1,BB1均垂直于A1B1,AA1=17,PP1=16,BB1=20,A1B1=12,则AP+PB等于(  ) A.12 B.13 C.14 D.15

问题描述:

如图,已知∠A=∠B,AA1,PP1,BB1均垂直于A1B1,AA1=17,PP1=16,BB1=20,A1B1=12,则AP+PB等于(  )
A. 12
B. 13
C. 14
D. 15

如图,AA1,PP1,BB1均垂直于A1B1,∴AA1∥PP1∥BB1,过点P作PF⊥AA1,交AA1于点D,交BB1于点F,延长BP交AA1于点C,作CG⊥BB1,交BB1于点G,∴四边形DFB1A1,DPP1A1,FPP1B1,FDGC,CGB1A1是矩形,∴DA1=PP1=FB1=16...