(1)(x-1)(x+1)-(x+1)^2(2)(10a^8-6a^5+2a)/(-2a) (3)x^-1(4)-8x^y^+2x^3y+8xy^
问题描述:
(1)(x-1)(x+1)-(x+1)^2(2)(10a^8-6a^5+2a)/(-2a) (3)x^-1(4)-8x^y^+2x^3y+8xy^
(1)(x-1)(x+1)-(x+1)^2(2)(10a^8-6a^5+2a)/(-2a)
(3)x^-1(4)-8x^y^+2x^3y+8xy^
答
(1)(x-1)(x+1)-(x+1)^2
=(x+1)(x-1-(x+1))
=-2(x+1)
(2)(10a^8-6a^5+2a)/(-2a)
=((-2a)(-5a^7+3a^4-1)/(-2a)
=-5a^7+3a^4-1
(3)x^-1
=1/x
(4)-8x^y^+2x^3y+8xy^
-8x^2y^2+2x^3y+8xy^2
=2xy(x^2-4xy+y)谢谢 不用了