Y=sin(x+兀/6)cos(兀/3-x)的最小正周期
问题描述:
Y=sin(x+兀/6)cos(兀/3-x)的最小正周期
答
Y=sin(x+兀/6)cos(兀/3-x)
=sin(x+兀/6)sin(x+兀/6)
=sin²(x+兀/6)
=[1-cos(2x+兀/3) ]/2
最小正周期T=2π/2=π