已知:sin(π+α)=-1/2 计算:sin(π/2+α) cos(α-3π/2) tan(π/2-α)

问题描述:

已知:sin(π+α)=-1/2 计算:sin(π/2+α) cos(α-3π/2) tan(π/2-α)

∵sin(π+α)=-1/2 ∴sinα= 1/2 sin(π/2+α)=cosα=√3/2 cos(α-3π/2)=-sinα=-1/2 tan(π/2-α)=√3 希望能对你有所帮助,