因式分解解下列方程:(2a-1)²=0 (2x-5)²=9 4x²-(x-1)²=0
问题描述:
因式分解解下列方程:(2a-1)²=0 (2x-5)²=9 4x²-(x-1)²=0
答
(2a-1)²=02a-1=0a=1/2(2x-5)²=9 (2x-5)²-3²=0(2x-5+3)(2x-5-3)=0(2x-2)(2x-8)=0x=1 x=44x²-(x-1)²=0(2x-x+1)(2x+x-1)=0(x+1)(3x-1)=0x=-1 x=1/3