(3√12-2√3分之1+√48)÷2√3 (1-2√3)(1+2√3)-(2√3-1)²

问题描述:

(3√12-2√3分之1+√48)÷2√3 (1-2√3)(1+2√3)-(2√3-1)²

(3√12-2√3分之1+√48)÷2√3
=(6√3-2√3/3+4√3)÷2√3
=3-1/3+2
=14/3
(1-2√3)(1+2√3)-(2√3-1)²
=1-(2√3)²-[(2√3)²-4√3+1)
=1-12-(12-4√3+1)
=-24+4√3