已知0〈α〈π/2,那么log(sinα)(1/(1-cos^2α))=? = =RT
问题描述:
已知0〈α〈π/2,那么log(sinα)(1/(1-cos^2α))=? = =RT
答
log(sinα)(1/(1-cos^2α))=log(sinα)(1/(sin^2α)=log(sinα)(sinα)^(-2)==-2
已知0〈α〈π/2,那么log(sinα)(1/(1-cos^2α))=? = =RT
log(sinα)(1/(1-cos^2α))=log(sinα)(1/(sin^2α)=log(sinα)(sinα)^(-2)==-2