求函数y=tan(x-π/3)的定义域
问题描述:
求函数y=tan(x-π/3)的定义域
答
y=tan(x-π/3)
x-π/3≠kπ+π/2
x≠kπ+5π/6
求函数y=tan(x-π/3)的定义域
y=tan(x-π/3)
x-π/3≠kπ+π/2
x≠kπ+5π/6