(1)(3x-2)^2=2(3x-2) (2)2x(5x-3)+(3-5x)^2=0
问题描述:
(1)(3x-2)^2=2(3x-2) (2)2x(5x-3)+(3-5x)^2=0
答
1) (3x-2)^2=2(3x-2)
9x^2-6x+4=6x-4
9x^2-12x+8=0
∆=(-12)^2-4*9*8