(文)在△ABC中,已知A=120°,且ACAB=23,则sinC=(  ) A.35738 B.3714 C.32114 D.31938

问题描述:

(文)在△ABC中,已知A=120°,且

AC
AB
2
3
,则sinC=(  )
A.
3
57
38

B.
3
7
14

C.
3
21
14

D.
3
19
38

∵ACAB=23,A=120°,∴设AC=2t,AB=3t,由余弦定理可得BC2=AC2+AB2-2AB•ACcos120°=(2t)2+(3t)2-2×2t×3t×(-12)=19t2,∴BC=19t,由正弦定理BCsinA=ABsinC,可得:sinC=ABBC×sinA=3t19t×32=35738故选...