若a为整数,a+12>0,a+10<0,则a2=_.

问题描述:

若a为整数,a+12>0,a+10<0,则a2=______.

∵a为整数,a+12>0,a+10<0,
∴a=-11,
∴a2=(-11)2=121.
故答案为:121.