先化简,再求值:2a-{-3b+[3a-2(3a-b)]},其中a=-1,b=-1/5
问题描述:
先化简,再求值:2a-{-3b+[3a-2(3a-b)]},其中a=-1,b=-1/5
答
2a-{-3b+[3a-2(3a-b)]},
=2a-(-3b+3a-6a+2b)
=2a-(-3a-b)
=2a+3a+b
=5a+b
=-1x5-1/5
=-26/5