复数z=1+i,则2/z+z2等于
问题描述：
复数z=1+i,则2/z+z2等于
答
2/z+z^2=2/(1+i)+(1+i)^2=2(1-i)/(1-i^2)+(1+i^2+2i)=(1-i) +2i =1+i =z
复数z=1+i,则2/z+z2等于
2/z+z^2=2/(1+i)+(1+i)^2=2(1-i)/(1-i^2)+(1+i^2+2i)=(1-i) +2i =1+i =z