1.(x-y)^5·(y-x)^4·(x-y)^3 2.a^2·a^3+a·a^5 3.2^2004x(-2)^2004x(-1/4)^2004

问题描述:

1.(x-y)^5·(y-x)^4·(x-y)^3 2.a^2·a^3+a·a^5 3.2^2004x(-2)^2004x(-1/4)^2004
计算!现在就要!
上面是有3小题

1.(x-y)^5·(y-x)^4·(x-y)^3
=(x-y)^5·(x-y)^4·(x-y)^3
=(x-y)^12
2.a^2·a^3+a·a^5
=a^5+a^6
3.2^2004x(-2)^2004x(-1/4)^2004
=[2×(-2)×(-1/4)]^2004
=1^2004
=1
祝学习快乐!第一题能详细一点吗?1.(x-y)^5·(y-x)^4·(x-y)^3 =(x-y)^5·(x-y)^4·(x-y)^3=(x-y)^(5+4+3)=(x-y)^12我的意思是:第一步:(x-y)^5·(x-y)^4·(x-y)^3中(x-y)^4是怎么由(y-x)^4变化来的,谢谢你可以这样理解(x-y)^4=[(-1)(x-y)]^4=(-1)^4(x-y)^4=(x-y)^4