如图,已知在锐角△ABC中,∠ABC=2∠C,∠ABC的平分线与AD垂直于D,求证:AC=2BD.
问题描述:
如图,已知在锐角△ABC中,∠ABC=2∠C,∠ABC的平分线与AD垂直于D,求证:AC=2BD.
答
证明:在BD上截取DF=DE,连接AF,∵DF=DE,AD⊥BF,AD=AD,∴△ADF≌△ADE,(3分)∴AE=AF,∠AFD=∠AEF∵∠ABC=2∠C,BE是∠ABC的平分线,∴∠ABE=∠C=∠EBC,∵∠AFE=∠ABE+∠BAF,∠AEF=∠EBC+∠C∴∠FAB=∠ABF...