f(x)=2sin(2x-三分之兀)+1,求函数的单调区间
问题描述：
f(x)=2sin(2x-三分之兀)+1,求函数的单调区间
答
f(x)=2sin(2x-π/3)+1当 2x-π/3∈[-π/2+2kπ,π/2+2kπ]单调递增,解得x∈[-π/12+kπ,5π/12+kπ]当 2x-π/3∈[π/2+2kπ,3π/2+2kπ]单调递减,解得x∈[5π/12+kπ,11π/12+kπ]单调增区间为[-π/12+kπ,5π/12+k...