1+1/1x2+1/2x3+1/3x4+...+1/2007x2008=?
问题描述:
1+1/1x2+1/2x3+1/3x4+...+1/2007x2008=?
答
1+1/1x2+1/2x3+1/3x4+...+1/2007x2008=1+(1-1/2)+(1/2-1/3)+(1/3-1/4)+.+(1/2007-1/2008)=2-1/2008.