化简sin(a-π)cot(a-2π)/cos(a-π)tan(a-2π)
问题描述：
化简sin(a-π)cot(a-2π)/cos(a-π)tan(a-2π)
答案是cota,我做出来是-cota 求解!
答
sin(a-π)cot(a-2π)/cos(a-π)tan(a-2π)
=-[sin(π-a)cota]/[cos(π-a)tana]
=-[sina*cota]/-[cosatana]
=cosa/sina
=cota