用洛必达定理求极限limx→-1根号π-根号arccosx/根号x+1
问题描述：
用洛必达定理求极限limx→-1根号π-根号arccosx/根号x+1
答
lim(√π-√arccosx)/(√(x+1))
=lim(1/2)(arccosx)^(-1/2)(1/√(1-x^2))/(1/2√(x+1))
=(1/2)(1/√π)(1/2)*2
=1/(2√π)