怎么解二元一次方程组.求m (8x=2m (-5x=m-8
问题描述:
怎么解二元一次方程组.求m (8x=2m (-5x=m-8
(8x=2m
(-5x=m-8
6x-10y=4m(1)
6x+21y=3m-24(2)
然后(1)-(2)
y=
答
常规思路:(1)8x=2m 得出m=4x
(2)-5x=m-8 得出m=-5X+8
(3)即4X=-5X+8 得出X=8/9
(4)M=4X =4*8/9=32/9