先化简,在求值:(x+y)(x-y)+(x-y)²-(x²-3xy)其中x=3,y=⅓

问题描述:

先化简,在求值:(x+y)(x-y)+(x-y)²-(x²-3xy)其中x=3,y=⅓

(x+y)(x-y)+(x-y)²-(x²-3xy)
=x²-y²+x²-2xy+y²-x²+3xy
=x²+xy
当x=3,y=1/3时
原式=9+1=10