根据复合函数微分法则y-sin(2x+1),求dy

问题描述:

根据复合函数微分法则y-sin(2x+1),求dy

y=sin(2x+1)
u=2x+1则u'=2
y=sinu
所以y'=cosu*u'
=2cos(2x+1)

y=sin(2x+1)
dy=dsin(2x+1)
=cos(2x+1)d(2x+1)
=2cos(2x+1)dx