a^2+6a+9分之4-a^2÷2a+6分之a-2+2
问题描述:
a^2+6a+9分之4-a^2÷2a+6分之a-2+2
答
=[-(a+2)(a-2)/(a+3)^2]×[2(a+3)/(a-2)]+2
=-2(a+2)/(a+3)+2
=(-2a-4+2a+6)/(a+3)
=2/(a+3)