设f(x)=cos2x+sinx 求f(π/3)的值
问题描述：
设f(x)=cos2x+sinx 求f(π/3)的值
答
f(π/3)=cos(2π/3)+sin(π/3)=-cos(π/3)+sin(π/3)=-1/2+(根号3)/2
设f(x)=cos2x+sinx 求f(π/3)的值
f(π/3)=cos(2π/3)+sin(π/3)=-cos(π/3)+sin(π/3)=-1/2+(根号3)/2