若xyz≠0,且 2x-y+6z=0,x+y-3z=0,则x+y/y-z=
问题描述:
若xyz≠0,且 2x-y+6z=0,x+y-3z=0,则x+y/y-z=
答
2x-y+6z=0,x+y-3z=0
将x、y用z表示出来,得
x=-z,y=4z
所以,x+y/y-z=(-1+4)/(4-1)=1