sin14/3π+cos(-23π/4)+tan(-25π/3)=?
问题描述:
sin14/3π+cos(-23π/4)+tan(-25π/3)=?
答
原式=sin(4π+2/3π)+cos(-6π+π/4)+tan(-8π-π/3)
=sin(2π/3)+cos(π/4)-tan(π/3)
=√3/2+√2/2-√3
=(-√3+√2)/2