sin²A+sinAcosA/sin²A+cos²A的化简
问题描述:
sin²A+sinAcosA/sin²A+cos²A的化简
sin²A+sinAcosA/sin²A+cos²A结果是tan²A+tanA/tan²A+1我想问下是怎么化简到那一步的,
答
(sin²A+sinAcosA)/(sin²A+cos²A) (分子分母同除以cos²A)
=(tan²A+tanA)/(tan²A+1)