2x分之1-x+y分之1(x的平方-y的平方+2x分之x+y),化简
问题描述:
2x分之1-x+y分之1(x的平方-y的平方+2x分之x+y),化简
答
2x分之1-x+y分之1(x的平方-y的平方+2x分之x+y)
=1/2x-1/(x+y)[(x-y)(x+y)+(x+y)/2x]
=1/2x-(x-y+1/2x)
=1/2x-x+y-1/2x
=y-x