f(x)=2sin^2-2根号3*sinX*cosX+1的周期怎么求
问题描述:
f(x)=2sin^2-2根号3*sinX*cosX+1的周期怎么求
如题,
答
f(x)=2sin^2-2√3*sinX*cosX+1 π
=1-cos2X-√3*sin2X+1
=2-2sin(2X+ π/3)
T=2 π/2= π