已知|x-2y-1|+x2+4xy+4y2=0,则x+y= _ .

问题描述:

已知|x-2y-1|+x2+4xy+4y2=0,则x+y= ___ .

∵|x-2y-1|+x2+4xy+4y2=|x-2y-1|+(x+2y)2=0,

x-2y-1=0
x+2y=0

解得:
x=
1
2
y=-
1
4

则x+y=
1
2
-
1
4
=
1
4

故答案为:
1
4