【sin30°/(sin60°-cos45°)】—(根号下(1—tan60°)²)—tan45°
问题描述:
【sin30°/(sin60°-cos45°)】—(根号下(1—tan60°)²)—tan45°
答
【sin30°/(sin60°-cos45°)】—(根号下(1—tan60°)²)—tan45°
=(1/2)/[√3/2-√2/2]-√(1-√3)²-1
=1/(√3-√2)-(√3-1)-1
=√3+√2-√3+1-1
=√2√ (1- √ 3)²怎么得到( √3-1)的√ (1- √ 3)²=|1- √ 3|= √3-1