求不定积分∫(tan^2)x dx
问题描述:
求不定积分∫(tan^2)x dx
答
∫(tan^2)x dx
=∫[(sec^2)x-1]dx
=tanx-x+C
求不定积分∫(tan^2)x dx
∫(tan^2)x dx
=∫[(sec^2)x-1]dx
=tanx-x+C