计算:﹙1-1∕2²﹚﹙1-1∕3²﹚……﹙1-1∕2003²﹚

问题描述:

计算:﹙1-1∕2²﹚﹙1-1∕3²﹚……﹙1-1∕2003²﹚

﹙1-1∕2²﹚﹙1-1∕3²﹚……﹙1-1∕2003²﹚=(1+1/2)﹙1-1∕2﹚(1+1/3)﹙1-1∕3﹚……(1+1/2003)﹙1-1∕2003﹚=3/2x4/3x……x2004/2003x1/2x2/3x……x2002/2003=2004/2x1/2003=2002/2003...