已知f(x)=asinx+btanx+1满足f(兀/5)=7.求f(99兀/5)
问题描述:
已知f(x)=asinx+btanx+1满足f(兀/5)=7.求f(99兀/5)
答
asin(兀/5)+btan(兀/5)=7-1=6
f(99兀/5)=f(20兀-兀/5)=asin(20兀-兀/5)+btan(20兀-兀/5)+1
=-6+1=-5