b^3n-1/a^2n-1×c÷b^3n-2/a^2n
问题描述:
b^3n-1/a^2n-1×c÷b^3n-2/a^2n
答
=a^(2n-1-2n-1)b^(3n-1-3n 2)c^2 =bc^2/a^2 27^2x÷9^x÷3^x=27 3^6x÷3^2x÷3^x=27 3^(6x-2x-x)=3^2 6x-2x-x=3
b^3n-1/a^2n-1×c÷b^3n-2/a^2n
=a^(2n-1-2n-1)b^(3n-1-3n 2)c^2 =bc^2/a^2 27^2x÷9^x÷3^x=27 3^6x÷3^2x÷3^x=27 3^(6x-2x-x)=3^2 6x-2x-x=3