十字相乘法:(x²+x+1)(x²+x+2)-6
问题描述:
十字相乘法:(x²+x+1)(x²+x+2)-6
答
(x²+x+1)(x²+x+2)-6=(x²+x)²+3(x²+x)-4=(x²+x-1)(x²+x+4)
十字相乘法:(x²+x+1)(x²+x+2)-6
(x²+x+1)(x²+x+2)-6=(x²+x)²+3(x²+x)-4=(x²+x-1)(x²+x+4)