2x-5+y/3=x+3y/4+7与10(x-y)-4(1-x)/3-y=0 求方程组的解
问题描述:
2x-5+y/3=x+3y/4+7与10(x-y)-4(1-x)/3-y=0 求方程组的解
答
由2x-5+y/3=x+3y/4+7 得x-5/12y-12=012x-5y -144=0 (1)由10(x-y)-4(1-x)/3-y=0 得 34/3x-11y-4/3=034x-33y-4=0 (2)(1)*33-(2)*5226x-4732=0x=2366/113代入 (1)式可解得y=2424/113.